Advertisements
Advertisements
Question
The area of a trapezium become 4 times if its height gets doubled.
Options
True
False
Advertisements
Solution
This statement is False.
Explanation:
We know that,
Area of a trapezium = `1/2 (a + b) xx h`
Where, a and b are the lengths of parallel sides and h is the altitude (height).
Now, if the height gets doubled, then
Area of trapezium = `1/2(a + b) xx 2h = 2(1/2(a + b) xx h)`
Hence, the area is doubled.
So, the statement is false.
APPEARS IN
RELATED QUESTIONS
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 8 m and 60 dm, altitude = 40 dm
Find the area of a trapezium whose parallel sides are of length 16 dm and 22 dm and whose height is 12 dm.
Find the altitude of a trapezium whose area is 65 cm2 and whose bases are 13 cm and 26 cm.
Find the area of a trapezium whose parallel sides of lengths 10 cm and 15 cm are at a distance of 6 cm from each other. Calculate this area as
the sum of the areas of two triangles and one rectangle.
If the area of a trapezium is 28 cm2 and one of its parallel sides is 6 cm, find the other parallel side if its altitude is 4 cm.
In Fig. 20.38, a parallelogram is drawn in a trapezium, the area of the parallelogram is 80 cm2, find the area of the trapezium.
Find the area of the field shown in Fig. 20.39 by dividing it into a square, a rectangle and a trapezium.
The following figure shows the cross-section ABCD of a swimming pool which is a trapezium in shape.
If the width DC, of the swimming pool, is 6.4 m, depth (AD) at the shallow end is 80 cm and depth (BC) at the deepest end is 2.4 m, find its area of the cross-section.
A ground is in the form of isosceles trapezium with parallel sides measuring 42 m and 36 m long. The distance between the parallel sides is 30 m. Find the cost of levelling it at the rate of ₹ 135 per sq.m
Find the area of the shaded portion in the following figure.
