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Question
The following figure shows the cross-section ABCD of a swimming pool which is a trapezium in shape.
If the width DC, of the swimming pool, is 6.4 m, depth (AD) at the shallow end is 80 cm and depth (BC) at the deepest end is 2.4 m, find its area of the cross-section.
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Solution
DC = 6.4 m
AD = 80 cm = `80/100` = 0.8 m
BC = 2.4 m
Area = ?
Area of the cross-section = Area of trapezium ABCD
= `1/2 ("Sum of parallel sides") xx "height"`
= `1/2 (0.8 + 2.4) xx 6.4`
= `1/2 xx 3.2 xx 6.4`
= 10.24 m2
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