Advertisements
Advertisements
प्रश्न
The following figure shows the cross-section ABCD of a swimming pool which is a trapezium in shape.
If the width DC, of the swimming pool, is 6.4 m, depth (AD) at the shallow end is 80 cm and depth (BC) at the deepest end is 2.4 m, find its area of the cross-section.
Advertisements
उत्तर
DC = 6.4 m
AD = 80 cm = `80/100` = 0.8 m
BC = 2.4 m
Area = ?
Area of the cross-section = Area of trapezium ABCD
= `1/2 ("Sum of parallel sides") xx "height"`
= `1/2 (0.8 + 2.4) xx 6.4`
= `1/2 xx 3.2 xx 6.4`
= 10.24 m2
APPEARS IN
संबंधित प्रश्न
Top surface of a raised platform is in the shape of a regular octagon as shown in the figure. Find the area of the octagonal surface.
Find the area of trapezium with base 15 cm and height 8 cm, if the side parallel to the given base is 9 cm long.
Find the height of a trapezium, the sum of the lengths of whose bases (parallel sides) is 60 cm and whose area is 600 cm2.
The area of a trapezium is 960 cm2. If the parallel sides are 34 cm and 46 cm, find the distance between them.
Top surface of a table is trapezium in shape. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m.
The area of a trapezium is 384 cm2. Its parallel sides are in the ratio 3 : 5 and the perpendicular distance between them is 12 cm. Find the length of each one of the parallel sides.
The area of a trapezium is 1080 sq.cm. If the lengths of its parallel sides are 55.6 cm and 34.4 cm. Find the distance between them
In a trapezium if the sum of the parallel sides is 10 cm and the area is 140 sq.cm, then the height is
The area of a trapezium become 4 times if its height gets doubled.
The area of a trapezium with equal non-parallel sides is 168 m2. If the lengths of the parallel sides are 36 m and 20 m, find the length of the non-parallel sides.
