Advertisements
Advertisements
प्रश्न
The parallel sides of a trapezium are in ratio 3: 4. If the distance between the parallel sides is 9 dm and its area is 126 dm2; find the lengths of its parallel sides.
Advertisements
उत्तर
Let parallel sides of trapezium be
a = 3x
b = 4x
Distance between parallel sides, h = 9 dm
area of trapezium = 126 dm2
`1/2 (a + b) xx h = 126`
`1/2 (3x + 4x) xx 9 = 126`
`7x xx 9 = 126 xx 2`
`x = (126 xx 2)/(7 xx 9)`
x = 4
a = 3x = 3 × 4 = 12 dm
b = 4x = 4 × 4 = 16 dm
12 dm , 16 dm
APPEARS IN
संबंधित प्रश्न
Find the area of a trapezium whose parallel sides are of length 16 dm and 22 dm and whose height is 12 dm.
The area of a trapezium is 1586 cm2 and the distance between the parallel sides is 26 cm. If one of the parallel sides is 38 cm, find the other.
The parallel sides of a trapezium are 25 cm and 13 cm; its nonparallel sides are equal, each being 10 cm, find the area of the trapezium.
If the area of a trapezium is 28 cm2 and one of its parallel sides is 6 cm, find the other parallel side if its altitude is 4 cm.
☐ PQRS is an isosceles trapezium l(PQ) = 7 cm. seg PM ⊥ seg SR, l(SM) = 3 cm, Distance between two parallel sides is 4 cm, find the area of ☐ PQRS.
The area of a trapezium is 279 sq.cm and the distance between its two parallel sides is 18 cm. If one of its parallel sides is longer than the other side by 5 cm, find the lengths of its parallel sides.
Find the area of a trapezium whose parallel sides are 24 cm and 20 cm and the distance between them is 15 cm
The area of a trapezium is 180 sq.cm and its height is 9 cm. If one of the parallel sides is longer than the other by 6 cm. Find the length of the parallel sides.
In a trapezium if the sum of the parallel sides is 10 cm and the area is 140 sq.cm, then the height is
Find the area of the shaded portion in the following figure.
