Advertisements
Advertisements
प्रश्न
The parallel sides of a trapezium are in ratio 3: 4. If the distance between the parallel sides is 9 dm and its area is 126 dm2; find the lengths of its parallel sides.
Advertisements
उत्तर

Let parallel sides of trapezium be
a = 3x
b = 4x
Distance between parallel sides, h = 9 dm
area of trapezium = 126 dm2
`1/2 (a + b) xx h = 126`
`1/2 (3x + 4x) xx 9 = 126`
`7x xx 9 = 126 xx 2`
`x = (126 xx 2)/(7 xx 9)`
x = 4
a = 3x = 3 × 4 = 12 dm
b = 4x = 4 × 4 = 16 dm
12 dm , 16 dm
APPEARS IN
संबंधित प्रश्न
Top surface of a raised platform is in the shape of a regular octagon as shown in the figure. Find the area of the octagonal surface.

Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 150 cm and 30 dm, altitude = 9 dm.
Find the area of a trapezium whose parallel sides of lengths 10 cm and 15 cm are at a distance of 6 cm from each other. Calculate this area as the difference of the area of a rectangle and the sum of the areas of two triangles.
If the area of a trapezium is 28 cm2 and one of its parallel sides is 6 cm, find the other parallel side if its altitude is 4 cm.
Find the area of the field shown in Fig. 20.39 by dividing it into a square, a rectangle and a trapezium.
Find the area enclosed by each of the following figures [Fig. 20.49 (i)-(iii)] as the sum of the areas of a rectangle and a trapezium:
Length of the two parallel sides of a trapezium are 8.5 cm and 11.5 cm respectively and its height is 4.2 cm, find its area.
Find the missing values.
| Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
| 16 cm | 15 cm | 360 sq.cm |
A window is in the form of trapezium whose parallel sides are 105 cm and 50 cm respectively and the distance between the parallel sides is 60 cm. Find the cost of the glass used to cover the window at the rate of ₹ 15 per 100 sq.cm
A trapezium with 3 equal sides and one side double the equal side can be divided into ______ equilateral triangles of ______ area.
