Advertisements
Advertisements
प्रश्न
The cross-section of a canal is a trapezium in shape. If the canal is 10 m wide at the top 6 m wide at the bottom and the area of cross-section is 72 m2 determine its depth.
Advertisements
उत्तर
Let the depth of canal bed.
Given:
Lengths of the parallel sides of the trapezium shape canal are 10 m and 6 m.
And, the area of the cross section of the canal is 72 m2 .
Area of trapezium \[=\frac{1}{2}\times(\text{ Sum of the parallel sides })\times(\text{ Perpendicular distance between the parallel sides })\]
\[72 = \frac{1}{2} \times (10+6)\times(d)\]
\[72 = 8\times d\]
\[d =\frac{72}{8}= 9 m\]
APPEARS IN
संबंधित प्रश्न
Find the area of trapezium with base 15 cm and height 8 cm, if the side parallel to the given base is 9 cm long.
Find the area of a trapezium whose parallel sides of lengths 10 cm and 15 cm are at a distance of 6 cm from each other. Calculate this area as
the sum of the areas of two triangles and one rectangle.
Find the area of Fig. as the sum of the areas of two trapezium and a rectangle.

In Fig. 20.38, a parallelogram is drawn in a trapezium, the area of the parallelogram is 80 cm2, find the area of the trapezium.
Find the missing values.
| Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
| 10 m | 12 m | 20 m |
The area of a trapezium is 1080 sq.cm. If the lengths of its parallel sides are 55.6 cm and 34.4 cm. Find the distance between them
The perimeter of a trapezium is 52 cm and its each non-parallel side is equal to 10 cm with its height 8 cm. Its area is ______.
A trapezium with 3 equal sides and one side double the equal side can be divided into ______ equilateral triangles of ______ area.
Find the area of the following fields. All dimensions are in metres.

Find the area of the shaded portion in the following figure.

