Advertisements
Advertisements
Question
Find the area of the field shown in Fig. 20.39 by dividing it into a square, a rectangle and a trapezium.
Advertisements
Solution
From the above figure:
Area of the figure=(Area of square AGFM with sides 4 cm)+(Area of rectangle MEDN with length 8 cm and width 4 cm)+(Area of trapezium NDCB with parallel sides 8 cm and 3 cm and perpendicular height 4 cm
\[= (4\times4)+(8\times4)+[\frac{1}{2}\times(8+3)\times(4)]\]
\[= 16+32+22\]
\[ {= 70 cm}^2\]
RELATED QUESTIONS
The area of a trapezium is 34 cm2 and the length of one of the parallel sides is 10 cm and its height is 4 cm. Find the length of the other parallel side.
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 8 m and 60 dm, altitude = 40 dm
Find the altitude of a trapezium whose area is 65 cm2 and whose bases are 13 cm and 26 cm.
Find the area of Fig. as the sum of the areas of two trapezium and a rectangle.
The cross-section of a canal is a trapezium in shape. If the canal is 10 m wide at the top 6 m wide at the bottom and the area of cross-section is 72 m2 determine its depth.
Length of the two parallel sides of a trapezium are 8.5 cm and 11.5 cm respectively and its height is 4.2 cm, find its area.
Find the missing values.
| Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
| 13 cm | 28 cm | 492 sq.cm |
Find the area of a trapezium whose parallel sides are 24 cm and 20 cm and the distance between them is 15 cm
The area of a trapezium is 1586 sq.cm. The distance between its parallel sides is 26 cm. If one of the parallel sides is 84 cm then find the other side
The areas of two circles are in the ratio 49 : 64. Find the ratio of their circumferences.
