Advertisements
Advertisements
Question
The area of a trapezium is 180 sq.cm and its height is 9 cm. If one of the parallel sides is longer than the other by 6 cm. Find the length of the parallel sides.
Advertisements
Solution
Let one of the parallel side be ‘a’ cm.
Given one parallel sides is longer than the other by 6 cm.
i.e. b = a + 6 cm
Also given height ‘h’ = 9 cm
Area of trapezium = 180 sq.cm
`1/2 xx "h" xx ("a" + "b")` = 180 cm2
`1/2 xx 9 xx ("a" + "a" + 6)` = 180
`1/2 xx 9 xx (2"a" + 6)` = 180
2a + 6 = `(180 xx 2)/9`
= 20 × 2
2a + 6 = 40
2a = 40 – 6
= 34
a = `34/2`
= 17 cm
b = a + 6
= 17 + 6
= 23 cm
∴ The parallel sides are a = 17 cm and b = 23 cm
APPEARS IN
RELATED QUESTIONS
The area of a trapezium is 34 cm2 and the length of one of the parallel sides is 10 cm and its height is 4 cm. Find the length of the other parallel side.
Find the area of Fig. as the sum of the areas of two trapezium and a rectangle.

The area of a trapezium is 1586 cm2 and the distance between the parallel sides is 26 cm. If one of the parallel sides is 38 cm, find the other.
Length of the two parallel sides of a trapezium are 8.5 cm and 11.5 cm respectively and its height is 4.2 cm, find its area.
The two parallel sides and the distance between them are in the ratio 3: 4: 2. If the area of the trapezium is 175 cm2, find its height.
The area of a trapezium is 279 sq.cm and the distance between its two parallel sides is 18 cm. If one of its parallel sides is longer than the other side by 5 cm, find the lengths of its parallel sides.
Find the missing values.
| Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
| 10 m | 12 m | 20 m |
The areas of two circles are in the ratio 49 : 64. Find the ratio of their circumferences.
Find the area of the following fields. All dimensions are in metres.

Find the area of the shaded portion in the following figure.

