Advertisements
Advertisements
Question
Find the area of a trapezium whose parallel sides are 24 cm and 20 cm and the distance between them is 15 cm
Advertisements
Solution
Given the parallel sides a = 24 cm, b = 20 cm
Distance between a and b is ‘h’ = 15 cm
Area of the trapezium = `1/2` × h × (a + b) sq.units
= `1/2` × 15 × (24 + 20) cm2
= `1/2` × 15 × 44 = 330 cm2
Area of the trapezium = 330 cm2
APPEARS IN
RELATED QUESTIONS
Find the altitude of a trapezium whose area is 65 cm2 and whose bases are 13 cm and 26 cm.
Find the area of a trapezium whose parallel sides of lengths 10 cm and 15 cm are at a distance of 6 cm from each other. Calculate this area as the difference of the area of a rectangle and the sum of the areas of two triangles.
The area of a trapezium is 1586 cm2 and the distance between the parallel sides is 26 cm. If one of the parallel sides is 38 cm, find the other.
The parallel sides of a trapezium are 25 cm and 13 cm; its nonparallel sides are equal, each being 10 cm, find the area of the trapezium.
Find the area of the field shown in Fig. 20.39 by dividing it into a square, a rectangle and a trapezium.
The two parallel sides and the distance between them are in the ratio 3: 4: 2. If the area of the trapezium is 175 cm2, find its height.
A window is in the form of trapezium whose parallel sides are 105 cm and 50 cm respectively and the distance between the parallel sides is 60 cm. Find the cost of the glass used to cover the window at the rate of ₹ 15 per 100 sq.cm
A ground is in the form of isosceles trapezium with parallel sides measuring 42 m and 36 m long. The distance between the parallel sides is 30 m. Find the cost of levelling it at the rate of ₹ 135 per sq.m
Arivu has a land ABCD with the measurements given in the figure. If a portion ABED is used for cultivation (where E is the mid-point of DC), find the cultivated area.
The areas of two circles are in the ratio 49 : 64. Find the ratio of their circumferences.
