Advertisements
Advertisements
Question
Find the area of a trapezium whose parallel sides are 24 cm and 20 cm and the distance between them is 15 cm
Advertisements
Solution
Given the parallel sides a = 24 cm, b = 20 cm
Distance between a and b is ‘h’ = 15 cm
Area of the trapezium = `1/2` × h × (a + b) sq.units
= `1/2` × 15 × (24 + 20) cm2
= `1/2` × 15 × 44 = 330 cm2
Area of the trapezium = 330 cm2
APPEARS IN
RELATED QUESTIONS
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 12 dm and 20 dm, altitude = 10 dm
The area of a trapezium is 960 cm2. If the parallel sides are 34 cm and 46 cm, find the distance between them.
The area of a trapezium is 384 cm2. Its parallel sides are in the ratio 3 : 5 and the perpendicular distance between them is 12 cm. Find the length of each one of the parallel sides.
The area of a trapezium is 279 sq.cm and the distance between its two parallel sides is 18 cm. If one of its parallel sides is longer than the other side by 5 cm, find the lengths of its parallel sides.
Find the missing values.
| Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
| 19 m | 16 m | 323 sq.m |
The sunshade of a window is in the form of isosceles trapezium whose parallel sides are 81 cm and 64 cm and the distance between them is 6 cm. Find the cost of painting the surface at the rate of ₹ 2 per sq.cm
When the non-parallel sides of a trapezium are equal then it is known as
The perimeter of a trapezium is 52 cm and its each non-parallel side is equal to 10 cm with its height 8 cm. Its area is ______.
Find the area of the following fields. All dimensions are in metres.

Find the area of the following fields. All dimensions are in metres.

