Advertisements
Advertisements
Question
The area of a trapezium is 1586 cm2 and the distance between the parallel sides is 26 cm. If one of the parallel sides is 38 cm, find the other.
Advertisements
Solution
Area of the trapezium = 1586 cm2
Distance between the parallel sides = 26 cm
And, length of one parallel side = 38 cm
Let us suppose the length of the other side to be x cm .
Now, area of the trapezium \[=\frac{1}{2}\times(\text{ Sum of the parallel sides })\times(\text{ Distance between the parallel sides })\]
\[ \Rightarrow 1586 =\frac{1}{2}\times(38+x)\times(26)\]
\[ \Rightarrow 1586=\frac{26}{2}\times(38+x)\]
\[ \Rightarrow 13\times(38+x)=1586\]
\[ \Rightarrow 38+x = \frac{1586}{13}=122\]
\[ \Rightarrow x = 122-38=84 cm\]
Hence, the length of the other parallel side is 84 cm.
RELATED QUESTIONS
Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.

Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 28 cm and 3 dm, altitude = 25 cm
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 150 cm and 30 dm, altitude = 9 dm.
Find the area enclosed by each of the following figures [Fig. 20.49 (i)-(iii)] as the sum of the areas of a rectangle and a trapezium:
Find the missing values.
| Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
| 19 m | 16 m | 323 sq.m |
Find the area of a trapezium whose parallel sides are 24 cm and 20 cm and the distance between them is 15 cm
The area of the trapezium, if the parallel sides are measuring 8 cm and 10 cm and the height 5 cm is
The areas of two circles are in the ratio 49 : 64. Find the ratio of their circumferences.
Find the area of the following fields. All dimensions are in metres.

Find the area of the shaded portion in the following figure.

