Advertisements
Advertisements
Question
The area of a trapezium is 1586 cm2 and the distance between the parallel sides is 26 cm. If one of the parallel sides is 38 cm, find the other.
Advertisements
Solution
Area of the trapezium = 1586 cm2
Distance between the parallel sides = 26 cm
And, length of one parallel side = 38 cm
Let us suppose the length of the other side to be x cm .
Now, area of the trapezium \[=\frac{1}{2}\times(\text{ Sum of the parallel sides })\times(\text{ Distance between the parallel sides })\]
\[ \Rightarrow 1586 =\frac{1}{2}\times(38+x)\times(26)\]
\[ \Rightarrow 1586=\frac{26}{2}\times(38+x)\]
\[ \Rightarrow 13\times(38+x)=1586\]
\[ \Rightarrow 38+x = \frac{1586}{13}=122\]
\[ \Rightarrow x = 122-38=84 cm\]
Hence, the length of the other parallel side is 84 cm.
APPEARS IN
RELATED QUESTIONS
The shape of the top surface of a table is a trapezium. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m.

Find the area of trapezium with base 15 cm and height 8 cm, if the side parallel to the given base is 9 cm long.
The parallel sides of a trapezium are 25 cm and 13 cm; its nonparallel sides are equal, each being 10 cm, find the area of the trapezium.
There is a pentagonal shaped park as shown in Fig. 20.50. Jyoti and Kavita divided it in two different ways.
Find the area of this park using both ways. Can you suggest some another way of finding its areas?
The following figure shows the cross-section ABCD of a swimming pool which is a trapezium in shape.

If the width DC, of the swimming pool, is 6.4 m, depth (AD) at the shallow end is 80 cm and depth (BC) at the deepest end is 2.4 m, find its area of the cross-section.
Find the area of a trapezium whose parallel sides are 24 cm and 20 cm and the distance between them is 15 cm
The area of a trapezium is 1586 sq.cm. The distance between its parallel sides is 26 cm. If one of the parallel sides is 84 cm then find the other side
The sunshade of a window is in the form of isosceles trapezium whose parallel sides are 81 cm and 64 cm and the distance between them is 6 cm. Find the cost of painting the surface at the rate of ₹ 2 per sq.cm
In a trapezium if the sum of the parallel sides is 10 cm and the area is 140 sq.cm, then the height is
When the non-parallel sides of a trapezium are equal then it is known as
