English

Mohan Wants to Buy a Trapezium Shaped Field. Its Side Along the River is Parallel and Twice the Side Along the Road. - Mathematics

Advertisements
Advertisements

Question

Mohan wants to buy a trapezium shaped field. Its side along the river is parallel and twice the side along the road. If the area of this field is 10500 m2 and the perpendicular distance between the two parallel sides is 100 m, find the length of the side along the river.

Sum
Advertisements

Solution

Given:

Area of the trapezium shaped field = 10500 m2 

It is also given that the length of the side along the river is double the length of the side along the road.

Let us suppose the length of the side along the road to be x.

Then, the length of the side along the river =\[ 2\times x = 2x\]

And, the perpendicular distance between these parallel sides =100 m

Area of trapezium \[=\frac{1}{2}\times(\text{ Sum of the parallel sides })\times(\text{ Perpendicular distance })\]

\[10500 = \frac{1}{2}\times(2x+x)\times(100)\]

\[10500=50\times(3x)\]

\[3x=\frac{10500}{50}=210\]

\[x=\frac{210}{3}=70 m\]

\[ \therefore\text{ Length of the side along the river }= 2\times x= 2\times70=140 m\]

shaalaa.com
  Is there an error in this question or solution?
Chapter 20: Mensuration - I (Area of a Trapezium and a Polygon) - Exercise 20.2 [Page 23]

APPEARS IN

RD Sharma Mathematics [English] Class 8
Chapter 20 Mensuration - I (Area of a Trapezium and a Polygon)
Exercise 20.2 | Q 14 | Page 23

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Top surface of a raised platform is in the shape of a regular octagon as shown in the figure. Find the area of the octagonal surface.


Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 8 m and 60 dm, altitude = 40 dm


Find the area of a trapezium whose parallel sides of lengths 10 cm and 15 cm are at a distance of 6 cm from each other. Calculate this area as
the sum of the areas of two triangles and one rectangle.


The area of a trapezium is 384 cm2. Its parallel sides are in the ratio 3 : 5 and the perpendicular distance between them is 12 cm. Find the length of each one of the parallel sides.


Length of the two parallel sides of a trapezium are 8.5 cm and 11.5 cm respectively and its height is 4.2 cm, find its area.


☐ PQRS is an isosceles trapezium l(PQ) = 7 cm. seg PM ⊥ seg SR, l(SM) = 3 cm, Distance between two parallel sides is 4 cm, find the area of ☐ PQRS.


The following figure shows the cross-section ABCD of a swimming pool which is a trapezium in shape. 

If the width DC, of the swimming pool, is 6.4 m, depth (AD) at the shallow end is 80 cm and depth (BC) at the deepest end is 2.4 m, find its area of the cross-section.


Find the missing values.

Height 'h' Parallel side 'a` Parallel side 'b` Area
19 m   16 m 323 sq.m

A ground is in the form of isosceles trapezium with parallel sides measuring 42 m and 36 m long. The distance between the parallel sides is 30 m. Find the cost of levelling it at the rate of ₹ 135 per sq.m


A trapezium with 3 equal sides and one side double the equal side can be divided into ______ equilateral triangles of ______ area.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×