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Question
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 8 m and 60 dm, altitude = 40 dm
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Solution
Given:
Bases:
8 m
And, 60 dm \[=\frac{60}{10}m = 6 m\]
Altitude = 40 dm \[=\frac{40}{10}m = 4 m\]
Area of trapezium \[ =\frac{1}{2}\times(\text{ Sum of the bases })\times(\text{ Altitude })\]
\[ = \frac{1}{2} \times (8 + 6) m \times (4) m\]
\[ = 28 \times m\times m\]
\[ {=28 m}^2 \]
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