Advertisements
Advertisements
प्रश्न
Find the area of the shaded portion in the following figure.
Advertisements
उत्तर
Area of shaded portion = Area of trapezium ABCH + Area of trapezium CDEF
Area of trapezium = `1/2` × (Sum of parallel sides) × (Height)
∴ Area of trapezium ABCH = `1/2 xx (12 + 6) xx 4`
= `1/2 xx 18 xx 4`
= 18 × 2
= 36 cm2
∴ Area of trapezium CDEF = `1/2 xx (8 + 16) xx 3`
= `(24 xx 3)/2`
= 36 cm2
Area of shaded portion = 36 + 36 = 72 cm2
APPEARS IN
संबंधित प्रश्न
The area of a trapezium is 34 cm2 and the length of one of the parallel sides is 10 cm and its height is 4 cm. Find the length of the other parallel side.
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 28 cm and 3 dm, altitude = 25 cm
Find the altitude of a trapezium whose area is 65 cm2 and whose bases are 13 cm and 26 cm.
The area of a trapezium is 91 cm2 and its height is 7 cm. If one of the parallel sides is longer than the other by 8 cm, find the two parallel sides.
The area of a trapezium is 1586 cm2 and the distance between the parallel sides is 26 cm. If one of the parallel sides is 38 cm, find the other.
Find the area of a trapezium whose parallel sides are 25 cm, 13 cm and the other sides are 15 cm each.
The following figure shows the cross-section ABCD of a swimming pool which is a trapezium in shape.
If the width DC, of the swimming pool, is 6.4 m, depth (AD) at the shallow end is 80 cm and depth (BC) at the deepest end is 2.4 m, find its area of the cross-section.
The area of a trapezium is 279 sq.cm and the distance between its two parallel sides is 18 cm. If one of its parallel sides is longer than the other side by 5 cm, find the lengths of its parallel sides.
Find the missing values.
| Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
| 16 cm | 15 cm | 360 sq.cm |
The area of a trapezium is 180 sq.cm and its height is 9 cm. If one of the parallel sides is longer than the other by 6 cm. Find the length of the parallel sides.
