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Question
Find the equivalent resistance between A and B
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Solution
6Ω and 3Ω are in parallel
`:.1/R_p= 1/R_1 + 1/R_2`
`:.R_(P_1) = 6.3/(6+3) = 18/9` = 2 Ω
4Ω and 2Ω are in parallel
`:. 1/R_P = 1/R_1 + 1/R_2`
`:. R_(P_2) = 4.12/(4+12) = 4.12/16 = 3 Ω`
`:. "Total" R_T = R_(P_1) + R_(P_2) = 2 + 3 = 5 Ω`
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