Advertisements
Advertisements
Question
Four resistances of 2.0Ω each are joined end to end, to form a square ABCD. Calculate the equivalent resistance of the combination between any two adjacent comers.
Advertisements
Solution
The diagram indicates a square ABCD formed by joining four resistances of 2Ω each, end to end.
Let us calculate the equivalent resistance of the combination B between the two adjacent comets C and D.
From given figure, arms DA, AB and BC are joined in series.
So, their equivalent of 6Ω and 2Ω are in parallel.
∴ The equivalent resistance of the combination is R.
Then, `1/"R" = 1/6 + 1/2 = 4/6 = 2/3`
∴ R = `3/2` Ω
= 1.5 Ω
RELATED QUESTIONS
If the equivalent resistance is to be increased, then the number of resistances should be connected in
- Series
- Parallel
- Mixed arrangement
- None of the above
Find the equivalent resistance between points A and B.
When a 4 Ω resistor is connected across the terminals of a 12 V battery, the number of coulombs passing through the resistor per second is:
(a) 0.3
(b) 3
(c) 4
(d) 12
Two resistances X and Y are connected turn by turn:
- in parallel, and
- in series.
In which case the resultant resistance will be less than either of the individual resistances?
Three resistors of 6Ω, 3Ω and 2Ω are connected together so that their total resistance is greater than 6Ω but less than 8Ω Draw a diagram to show this arrangement and calculate its total resistance.
Two resistors of 4Ω and 6Ω are connected in parallel to a cell to draw 0.5 A current from the cell.
Draw a labelled circuit diagram showing the above arrangement.
Two wires of the same length and area made of two materials of resistivity ρ1 and ρ2 are connected in series to a source of potential V. The equivalent resistivity for the same area is:
If R1 and R2 be the resistance of the filament of 40 W and 60 W respectively operating 220 V, then:
Consider the following combinations of resistors:
The combinations having equivalent resistance 1 Q is/are ______.
