Advertisements
Advertisements
Question
State expression for Resistance connected in series.
Advertisements
Solution
R = r1 + r2 + r3, resistances in series.
RELATED QUESTIONS
Complete the following :-
(a)

(i) Two sets A and B, of three bulbs each, are glowing in two separate rooms. When one of the bulbs in set A is fused, the other two bulbs also cease to glow. But in set B, when one bulb fuses, the other two bulbs continue to glow. Explain why this phenomenon occurs.
(ii) Why do we prefer arrangements of Set B for house circuiting?
If the length of a wire is doubled by taking more of wire, what happens to its resistance?
What is the equivalent resistance between A and B in the given circuit (Fig?)

You have three resistors of values 2 `Omega`, 3 `Omega`, and 5 `Omega`. How will you join them so that the total resistance is less than 2 `Omega`?
Write an expression for calculating electrical power in terms of current and resistance.
Two lamps of resistance 30Ω and 20Ω respectively are connected in series in a 110V circuit. Calculate:
(i) the total resistance in the circuit
(ii) the current in the circuit, and
(iii) the voltage drop across each lamp.
Calculate the value of the resistance which must be connected to a 15 ohm resistance to provide on effective resistance of 6 ohm.
The resistance of two resistors joined in series is 8Ω and in parallel is 1.5Ω. Find the value of the two resistances.
