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Question
Find the equation of a line passing through the point (2, 3) and parallel to the line 3x − 4y + 5 = 0.
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Solution
The equation of the line parallel to 3x − 4y + 5 = 0 is \[3x - 4y + \lambda = 0\] , where
\[\lambda\] is a constant.
It passes through (2, 3).
\[\therefore\] \[6 - 12 + \lambda = 0\]
\[ \Rightarrow \lambda = 6\]
Hence, the required line is 3x − 4y + 6 = 0.
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