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Question
The inclination of the straight line passing through the point (−3, 6) and the mid-point of the line joining the point (4, −5) and (−2, 9) is
Options
π/4
π/6
π/3
3 π/4
5 π/6
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Solution
3 π/4
The midpoint of the line joining the points (4, −5) and (−2, 9) is (1, 2).
Let \[\theta\] be the inclination of the straight line passing through the points (−3, 6) and (1, 2).
\[\text { Then }, \tan \theta = \frac{2 - 6}{1 + 3} = - 1\]
\[ \Rightarrow \theta = \frac{3\pi}{4}\]
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