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Question
Find the equation of the straight line passing through the point (6, 2) and having slope − 3.
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Solution
Here,
\[m = - 3, x_1 = 6 \text { and } y_1 = 2\]
Substituting these values in \[y - y_1 = m\left( x - x_1 \right)\] , we get,
\[y - 2 = - 3\left( x - 6 \right)\]
\[ \Rightarrow y - 2 = - 3x + 18\]
\[ \Rightarrow 3x + y - 20 = 0\]
Hence, the equation of the required line is \[3x + y - 20 = 0\]
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