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Question
The equation of the line passing through the point (1, 2) and perpendicular to the line x + y + 1 = 0 is ______.
Options
y – x + 1 = 0
y – x – 1 = 0
y – x + 2 = 0
y – x – 2 = 0
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Solution
The equation of the line passing through the point (1, 2) and perpendicular to the line x + y + 1 = 0 is y – x – 1 = 0.
Explanation:
Equation of any line perpendicular to the given line x + y + 1 = 0 is x – y + k = 0 ......(i)
If equation (i) passes through the point (1, 2)
Then 1 – 2 + k = 0
⇒ k = 1
Putting the value of k is equation (i) we have
x – y + 1 = 0
⇒ y – x – 1 = 0
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