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The equation of the straight line passing through the point (3, 2) and perpendicular to the line y = x is ______.

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Question

The equation of the straight line passing through the point (3, 2) and perpendicular to the line y = x is ______.

Options

  • x – y = 5

  • x + y = 5

  • x + y = 1

  • x – y = 1

MCQ
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Solution

The equation of the straight line passing through the point (3, 2) and perpendicular to the line y = x is x + y = 5.

Explanation:


Equation of line ‘l’ is given by y – y1 = m(x – x1).

Since l passing through the point P(3, 2).

∴ y – 2 = m(x – 3)

⇒ y = mx + 2 – 3m   .....(i)

Since it is given that lines y = x

And ‘l’ are perpendicular to each other

∴ `"m" xx1`= –1   .....`[because "m"_1 xx "m"_2 = - 1]`

m = –1

Put m = – 1 in eqn. (i), we get

y = –x + 2 – 3(–1)

y = –x + 5

x + y = 5

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Chapter 10: Straight Lines - Exercise [Page 180]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 10 Straight Lines
Exercise | Q 24 | Page 180

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