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The equation of the line passing through the point (1, 2) and perpendicular to the line x + y + 1 = 0 is ______. - Mathematics

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प्रश्न

The equation of the line passing through the point (1, 2) and perpendicular to the line x + y + 1 = 0 is ______.

विकल्प

  • y – x + 1 = 0

  • y – x – 1 = 0

  • y – x + 2 = 0

  • y – x – 2 = 0

MCQ
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उत्तर

The equation of the line passing through the point (1, 2) and perpendicular to the line x + y + 1 = 0 is y – x – 1 = 0.

Explanation:

Equation of any line perpendicular to the given line x + y + 1 = 0 is x – y + k = 0  ......(i)

If equation (i) passes through the point (1, 2)

Then 1 – 2 + k = 0

⇒ k = 1

Putting the value of k is equation (i) we have

x – y + 1 = 0

⇒ y – x – 1 = 0

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Equations of Line in Different Forms - Equation of Family of Lines Passing Through the Point of Intersection of Two Lines
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अध्याय 10: Straight Lines - Exercise [पृष्ठ १८०]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 10 Straight Lines
Exercise | Q 25 | पृष्ठ १८०

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