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Find the Equation of a Line Equidistant from the Lines Y = 10 and Y = − 2. - Mathematics

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प्रश्न

Find the equation of a line equidistant from the lines y = 10 and y = − 2.

संक्षेप में उत्तर
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उत्तर

The lines y = 10 and y = −2 pass through the points (0, 10) and (0, −2), respectively. Let (h, k) be the mid-point of the line joining the points (0, 10) and (0, −2).

\[\therefore \left( h, k \right) = \left( 0, \frac{10 - 2}{2} \right) = \left( 0, 4 \right)\]

The given lines are parallel to the x-axis and the required line is equidistant from these lines.
Hence, the required line is parallel to the x-axis, which is given by y = k.
This line passes through (0, 4).
∴ 4 = k

\[\Rightarrow\] k = 4
Hence, the equation of a line that is equidistant from the lines y = 10 and y = − 2 is y = 4..

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Equations of Line in Different Forms - Equation of Family of Lines Passing Through the Point of Intersection of Two Lines
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अध्याय 23: The straight lines - Exercise 23.2 [पृष्ठ १७]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 23 The straight lines
Exercise 23.2 | Q 7 | पृष्ठ १७

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