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A Line Passes Through the Point (2, 2) and is Perpendicular to the Line 3x + Y = 3. Its Y-intercept is

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प्रश्न

A line passes through the point (2, 2) and is perpendicular to the line 3x + y = 3. Its y-intercept is

विकल्प

  • \[\frac{1}{3}\]

  • 2/3

  • 1

  • 4/3

MCQ
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उत्तर

4/3

The equation of the line perpendicular to 3x + y = 3 is given below:

x \[-\] 3y + \[\lambda\] = 0

This line passes through (2, 2)

2 \[-\] 6 + \[\lambda\] = 0

\[\Rightarrow \lambda = 4\]

So, the equation of the line will be

x\[-\] 3y + 4 = 0 

\[\Rightarrow y = \frac{1}{3}x + \frac{4}{3}\]

Hence, the y-intercept is \[\frac{4}{3}\].

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Equations of Line in Different Forms - Equation of Family of Lines Passing Through the Point of Intersection of Two Lines
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 23: The straight lines - Exercise 23.21 [पृष्ठ १३३]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 23 The straight lines
Exercise 23.21 | Q 6 | पृष्ठ १३३

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