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In What Ratio is the Line Joining the Points (2, 3) and (4, −5) Divided by the Line Passing Through the Points (6, 8) and (−3, −2).

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प्रश्न

In what ratio is the line joining the points (2, 3) and (4, −5) divided by the line passing through the points (6, 8) and (−3, −2).

संक्षेप में उत्तर
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उत्तर

The equation of the line joining the points (6, 8) and (−3, −2) is

\[y - 8 = \frac{- 2 - 8}{- 3 - 6}\left( x - 6 \right)\]

\[ \Rightarrow 10x - 9y + 12 = 0\]

Let 10x − 9y + 12 = 0 divide the line joining the points (2, 3) and (4, −5) at point P in the ratio k : 1

\[\therefore P \equiv \left( \frac{4k + 2}{k + 1}, \frac{- 5k + 3}{k + 1} \right)\]

P lies on the line 10x − 9y + 12 = 0

\[\therefore 10\left( \frac{4k + 2}{k + 1} \right) - 9\left( \frac{- 5k + 3}{k + 1} \right) + 12 = 0\]

\[ \Rightarrow 40k + 20 + 45k - 27 + 12k + 12 = 0\]

\[ \Rightarrow 97k + 5 = 0\]

\[ \Rightarrow k = - \frac{5}{97}\]

Hence, the line joining the points (2, 3) and (4, −5) is divided by the line passing through the points (6, 8) and (−3, −2) in the ratio 5 : 97 externally.

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Equations of Line in Different Forms - Equation of Family of Lines Passing Through the Point of Intersection of Two Lines
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अध्याय 23: The straight lines - Exercise 23.5 [पृष्ठ ३५]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 23 The straight lines
Exercise 23.5 | Q 9 | पृष्ठ ३५

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