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Find the Equation of the Straight Line Passing Through the Origin and Bisecting the Portion of the Line Ax + by + C = 0 Intercepted Between the Coordinate Axes.

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प्रश्न

Find the equation of the straight line passing through the origin and bisecting the portion of the line ax + by + c = 0 intercepted between the coordinate axes.

संक्षेप में उत्तर
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उत्तर

The equation of the line passing through the origin is y = mx.
Let the line ax + by + c = 0 meet the coordinate axes at A and B.
So, the coordinates of A and B are \[A \left( - \frac{c}{a}, 0 \right) \text { and }B \left( 0, - \frac{c}{b} \right)\].

Now, the midpoint of AB is \[\left( - \frac{c}{2a}, - \frac{c}{2b} \right)\].

Clearly, \[\left( - \frac{c}{2a}, - \frac{c}{2b} \right)\] lies on the line y = mx.

\[\therefore - \frac{c}{2b} = m \times \frac{- c}{2a}\]

\[ \Rightarrow m = \frac{a}{b}\] 

Hence, the equation of the required line is 

\[y = \frac{a}{b}x\]

\[ \Rightarrow ax - by = 0\]

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Equations of Line in Different Forms - Equation of Family of Lines Passing Through the Point of Intersection of Two Lines
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अध्याय 23: The straight lines - Exercise 23.6 [पृष्ठ ४७]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 23 The straight lines
Exercise 23.6 | Q 19 | पृष्ठ ४७

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