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Equation of the line passing through the point (a cos3θ, a sin3θ) and perpendicular to the line x sec θ + y cosec θ = a is x cos θ – y sin θ = a sin 2θ. - Mathematics

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प्रश्न

Equation of the line passing through the point (a cos3θ, a sin3θ) and perpendicular to the line x sec θ + y cosec θ = a is x cos θ – y sin θ = a sin 2θ.

विकल्प

  • True

  • False

MCQ
सत्य या असत्य
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उत्तर

This statement is False.

Explanation:

Equation of any line perpendicular to x sec θ + y cosec θ = a is 

x cosec θ – y sec θ = k   .......(i)

If equation (i) passes through (a cos3θ, a sin3θ) then

a cos3θ.cosec θ – a sin3θ.secθ = k

⇒ `(a cos^3 theta)/sintheta - (asin^3theta)/costheta` = k

∴ Required equation is

x cos θ – y sin θ = `(a cos^3 theta)/sintheta - (asin^3theta)/costheta` 

⇒ `x/sintheta - y/costheta = a[(cos^4theta - sin^4theta)/(sintheta costheta)]`

⇒ `(xcostheta - ysintheta)/(sintheta costheta) = a[((cos^2theta + sin^2theta)(cos^2theta - sin^2theta))/(sintheta costheta)]`

⇒ x cos θ – y sin θ = a(cos2θ – sin2θ)

⇒ x cos θ – y sin θ = a cos 2θ.

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Equation of a Straight Line - Equation of Family of Lines Passing Through the Point of Intersection of Two Lines
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अध्याय 10: Straight Lines - Exercise [पृष्ठ १८३]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 10 Straight Lines
Exercise | Q 50 | पृष्ठ १८३

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