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Find the Equation of the Straight Line Passing Through (3, −2) and Making an Angle of 60° with the Positive Direction of Y-axis.

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प्रश्न

Find the equation of the straight line passing through (3, −2) and making an angle of 60° with the positive direction of y-axis.

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उत्तर

The graph of the required line is shown below.

The line which is inclined at an angle of 60° with the positive direction of y-axis makes an angle of 30° with x-axis.
Clearly, the slope of the required line is \[m = \tan {30}^\circ = \frac{1}{\sqrt{3}}\]

So, the equation of the required line having slope \[\frac{1}{\sqrt{3}}\] and passes through the point \[P\left( 3, - 2 \right)\] is

\[y + 2 = \frac{1}{\sqrt{3}}\left( x - 3 \right)\]

\[ \Rightarrow x - \sqrt{3}y - 3 - 2\sqrt{3} = 0\] 

Hence, the equation of the required line is \[x - \sqrt{3}y - 3 - 2\sqrt{3} = 0\]

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Equations of Line in Different Forms - Equation of Family of Lines Passing Through the Point of Intersection of Two Lines
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अध्याय 23: The straight lines - Exercise 23.4 [पृष्ठ २९]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 23 The straight lines
Exercise 23.4 | Q 6 | पृष्ठ २९

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