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Find the Equation of a Line Making an Angle of 150° with the X-axis and Cutting off an Intercept 2 from Y-axis. - Mathematics

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प्रश्न

Find the equation of a line making an angle of 150° with the x-axis and cutting off an intercept 2 from y-axis.

संक्षेप में उत्तर
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उत्तर

Here, 

\[m = \tan {150}^\circ = - \tan {30}^\circ = - \frac{1}{\sqrt{3}}\]

and c = y-intercept = 2
Substituting the values of m and c in y = mx + c, we get,

\[y = - \frac{1}{\sqrt{3}}x + 2\]

\[ \Rightarrow x + \sqrt{3}y = 2\sqrt{3}\]

Hence, the equation of the required line is

\[x + \sqrt{3}y = 2\sqrt{3}\].
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अध्याय 23: The straight lines - Exercise 23.3 [पृष्ठ २१]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 23 The straight lines
Exercise 23.3 | Q 1 | पृष्ठ २१
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