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Question
Draw a formula for the first five members of the homologous series beginning with the given compound.
H–COOH
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Solution
The first five members of the homologous series beginning with the given compound are
H–COOH : Methanoic acid
CH3–COOH : Ethanoic acid
CH3–CH2–COOH : Propanoic acid
CH3–CH2–CH2–COOH : Butanoic acid
CH3–CH2–CH2–CH2–COOH : Pentanoic acid
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\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{...................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
\phantom{}|\phantom{....}|\phantom{...............}\\
\phantom{}\ce{CH3}\phantom{.}\ce{CH3}\phantom{.............}
\end{array}\]
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\[\ce{CH3 -CH2 -\overset{⊕}{C}H -CH2 -CH3}\]
Identify primary, secondary, tertiary and quaternary carbon in the following compound.
\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{....}|\phantom{................}\\
\ce{CH3}\ce{CH3}\phantom{..............}
\end{array}
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\[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{....}|\phantom{................}\\
\ce{CH3}\phantom{.}\ce{CH3}\phantom{..............}
\end{array}\]
