Advertisements
Advertisements
Question
Draw a formula for the first five members of the homologous series beginning with the given compound.
H–CH=CH2
Advertisements
Solution
The first five members of each homologous series beginning with the given compounds are
H–CH=CH2 : Ethene
CH3–CH=CH2 : Propene
CH3–CH2–CH=CH2 : 1-Butene
CH3–CH2–CH2–CH=CH2 : 1-Pentene
CH3–CH2–CH2–CH2–CH=CH2 : 1-Hexene
APPEARS IN
RELATED QUESTIONS
Identify the functional group in the following compound.

Identify the functional group in the following compound.

Find out all the functional groups present in the following polyfunctional compound.
Penicillin G, a naturally occurring antibiotic.

Identify primary, secondary, tertiary, and quaternary carbon in the following compound.
\[\begin{array}{cc}\ce{CH3}\phantom{..................}\\
|\phantom{....................}\\\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\|\phantom{.....}|\phantom{................}\\
\ce{CH3}\phantom{.}\ce{CH3}\phantom{..............}
\end{array}\]
What is meant by homologous series?
Structure of the compound whose IUPAC name is 5, 6 – dimethylhept - 2 - ene is
Describe the classification of organic compounds based on their structure.
Write a note on homologous series.
Write the molecular formula and possible structural formula of the first four members of homologous series of carboxylic acids.
The reagent used to confirm the presence of five hydroxyl groups in glucose is ____________.
Identify the pair of organic compounds which belongs to homologous series.
Which of the following yields only one type of monosubstituted chloroalkane upon chlorination?
Which of the following is NOT a cyclic compound?
What is the molecular formula of pyran?
How many primary, secondary and tertiary carbon atoms respectively are present in isobutane?

A and B are:
Identify the α - carbons in the following species and give the total number of α-hydrogen in each.
\[\ce{CH3 - CH2 - \overset{\oplus}{C}H - CH2 - CH3}\]
Identify primary, secondary, tertiary and quaternary carbon in the following compound.
\[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{....}|\phantom{................}\\
\ce{CH3}\phantom{.}\ce{CH3}\phantom{..............}
\end{array}\]
