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Question
Draw a formula for the first five members of the homologous series beginning with the given compound.
H–CH=CH2
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Solution
The first five members of each homologous series beginning with the given compounds are
H–CH=CH2 : Ethene
CH3–CH=CH2 : Propene
CH3–CH2–CH=CH2 : 1-Butene
CH3–CH2–CH2–CH=CH2 : 1-Pentene
CH3–CH2–CH2–CH2–CH=CH2 : 1-Hexene
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\[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{....}|\phantom{................}\\
\ce{CH3} \ce{CH3}\phantom{..............}
\end{array}\]
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\[\begin{array}{cc}
\ce{CH3\phantom{.................}}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{....}|\phantom{................}\\
\ce{CH3 CH3\phantom{.............}}
\end{array}\]
Identify primary, secondary, tertiary and quaternary carbon in the following compound:
\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{....}|\phantom{................}\\
\ce{CH3}\phantom{.}\ce{CH3}\phantom{..............}\\
\end{array}\]
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\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{....}|\phantom{................}\\
\ce{CH3}\phantom{.}\ce{CH3}\phantom{..............}
\end{array}\]
Identify primary, secondary, tertiary and quaternary carbon in the following compound.
\[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{....}|\phantom{................}\\
\ce{CH3}\phantom{.}\ce{CH3}\phantom{..............}
\end{array}\]
