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प्रश्न
Draw a formula for the first five members of the homologous series beginning with the given compound.
H–CH=CH2
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उत्तर
The first five members of each homologous series beginning with the given compounds are
H–CH=CH2 : Ethene
CH3–CH=CH2 : Propene
CH3–CH2–CH=CH2 : 1-Butene
CH3–CH2–CH2–CH=CH2 : 1-Pentene
CH3–CH2–CH2–CH2–CH=CH2 : 1-Hexene
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Identify primary, secondary, tertiary, and quaternary carbon in the following compounds.
\[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
\phantom{}|\phantom{....}|\phantom{................}\\
\phantom{.}\ce{CH3\phantom{.}CH3}\phantom{..............}
\end{array}\]
Identify primary, secondary, tertiary and quaternary carbon in the following compound.
\[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{....}|\phantom{................}\\
\ce{CH3}\phantom{..}\ce{CH3}\phantom{..............}\\
\end{array}\]
Identify primary, secondary, tertiary and quaternary carbon in the following compound.
\[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{....}|\phantom{................}\\
\ce{CH3}\ce{CH3}\phantom{..............}
\end{array}\]
Identify the α - carbons in the following species and give the total number of α-hydrogen in each.
\[\ce{CH3 - CH2 - \overset{\oplus}{C}H - CH2 - CH3}\]
Identify the α-carbons in the following species and give the total number of α-hydrogen.
\[\ce{CH2 = CH - CH2 - CH3}\]
Identify primary, secondary, tertiary and quaternary carbon in the following compound.
\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{.....}|\phantom{................}\\
\ce{CH3}\phantom{.}\ce{CH3}\phantom{..............}
\end{array}\]
Identify primary, secondary, tertiary and quaternary carbon in the following compound.
\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{....}|\phantom{................}\\
\ce{CH3}\phantom{.}\ce{CH3}\phantom{..............}
\end{array}\]
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