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Question
How many cyclic and acyclic isomers are possible for the molecular formula C3H6O?
Options
4
5
9
10
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Solution
9
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\[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
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\[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
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\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
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\ce{CH3}\phantom{.}\ce{CH3}\phantom{..............}
\end{array}\]
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\[\ce{CH3 - CH2 - \overset{\oplus}{C}H - CH2 - CH3}\]
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\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
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\[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
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