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प्रश्न
Draw a formula for the first five members of the homologous series beginning with the given compound.
H–COOH
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उत्तर
The first five members of the homologous series beginning with the given compound are
H–COOH : Methanoic acid
CH3–COOH : Ethanoic acid
CH3–CH2–COOH : Propanoic acid
CH3–CH2–CH2–COOH : Butanoic acid
CH3–CH2–CH2–CH2–COOH : Pentanoic acid
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\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{.....}|\phantom{...............}\\
\ce{CH3}\phantom{..}\ce{CH3}\phantom{.............}
\end{array}\]
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\[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{....}|\phantom{................}\\
\ce{CH3} \ce{CH3}\phantom{..............}
\end{array}\]
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\[\begin{array}{cc}
\ce{CH3\phantom{.................}}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{....}|\phantom{................}\\
\ce{CH3 CH3\phantom{.............}}
\end{array}\]
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\[\ce{CH3 - CH2 - \overset{\oplus}{C}H - CH2 - CH3}\]
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\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{....}|\phantom{................}\\
\ce{CH3}\phantom{.}\ce{CH3}\phantom{..............}\\
\end{array}\]
Identify primary, secondary, tertiary and quaternary carbon in the following compound.
\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{.....}|\phantom{................}\\
\ce{CH3}\phantom{.}\ce{CH3}\phantom{..............}
\end{array}\]
