Advertisements
Advertisements
Question
Write the first four members of the homologous series that begins with H-C≡C-H. Also, write down their general molecular formula.
Advertisements
Solution
| No. | Name of a compound and molecular formula | Structural formula |
| 1. | Ethyne (C2H2) | HC ≡ CH |
| 2. | Propyne (C3H4) | CH3 - C ≡ CH |
| 3. | But-1-yne (C4H6) | CH3 - CH2 - C ≡ CH |
| 4. | Pent-1-yne (C5H8) | CH3 - CH2 - CH2 - C ≡ CH |
Comparing these molecular formulae and assigning the number of carbon atoms as ‘n’, the following general formula is deduced: CnH2n - 2 (where n = 2, 3, 4...)
APPEARS IN
RELATED QUESTIONS
Identify the functional group in the following compound.
Identify the functional group in the following compound.
Identify the functional group in the following compound.
Find out all the functional groups present in the following polyfunctional compound.
Thyroxine, the principal thyroid hormone.
Identify primary, secondary, tertiary, and quaternary carbon in the following compound.
\[\begin{array}{cc}\ce{CH3}\phantom{..................}\\
|\phantom{....................}\\\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\|\phantom{.....}|\phantom{................}\\
\ce{CH3}\phantom{.}\ce{CH3}\phantom{..............}
\end{array}\]
What is meant by homologous series?
Write the first four members of the homologous series that begins with CH3CHO. Also, write down their general molecular formula.
Structure of the compound whose IUPAC name is 5, 6 – dimethylhept - 2 - ene is
How many cyclic and acyclic isomers are possible for the molecular formula C3H6O?
The reagent used to confirm the presence of five hydroxyl groups in glucose is ____________.
An organic compound containing carbon, hydrogen and oxygen is soluble in dil. H2SO4 and does not react with sodium metal or KMnO4. When it is heated with HI in excess, a single alkyl halide is obtained. The original compound can be ____________.
How many 3° carbon atoms are present in 1, 4 dibromo-2-methylpentane?
Identify the number of carbon atoms and number of oxygen atoms respectively present in pyran molecule.
An organic compound 'X' (molecular formula C6H7O2N) has six carbons in a ring system, two double bonds and also a nitro group as a substituent, 'X' is ______.
A pyranose ring consists of a skeleton of ______.
Identify primary, secondary, tertiary, and quaternary carbon in the following compound.
\[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{....}|\phantom{................}\\
\ce{CH3} \ce{CH3}\phantom{..............}
\end{array}\]
Identify primary, secondary, tertiary and quaternary carbon in the following compounds.
\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{...................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
\phantom{}|\phantom{....}|\phantom{...............}\\
\phantom{}\ce{CH3}\phantom{.}\ce{CH3}\phantom{.............}
\end{array}\]
Identify primary, secondary, tertiary and quaternary carbon in the following compound.
\[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{....}|\phantom{................}\\
\ce{CH3}\ce{CH3}\phantom{..............}
\end{array}\]
Identify primary, secondary, tertiary and quaternary carbon in the following compound.
\[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{....}|\phantom{................}\\
\ce{CH3}\phantom{.}\ce{CH3}\phantom{..............}
\end{array}\]
Identify primary, secondary, tertiary and quaternary carbon in the following compound.
\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{....}|\phantom{................}\\
\ce{CH3}\ce{CH3}\phantom{..............}
\end{array}
Indicate the σ and π bonds in the following molecule:
\[\ce{HCONHCH3}\]
Identify primary, secondary, tertiary and quaternary carbon in the following compound.
\[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{....}|\phantom{................}\\
\ce{CH3}\phantom{.}\ce{CH3}\phantom{..............}
\end{array}\]
