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Question
Write the first four members of the homologous series that begins with CH3CHO. Also, write down their general molecular formula.
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Solution
| No. | Name of compound and molecular formula | Structural formula |
| 1. | Acetaldehyde (CH3CHO) |
\[\begin{array}{cc}\phantom{...}\ce{O}\\ |
| 2. | Propionaldehyde (C2H5CHO) | \[\begin{array}{cc}\phantom{..........}\ce{O}\\ \phantom{..........}||\\\ce{H3C - CH2 - C - H}\end{array}\] |
| 3. | Butyraldehyde (C3H7CHO) | \[\begin{array}{cc}\phantom{.................}\ce{O}\\ \phantom{.................}||\\\ce{H3C - CH2 - CH2 - C - H}\end{array}\] |
| 4. | Valeraldehyde (C4H9CHO) | \[\begin{array}{cc}\phantom{....................}\ce{O}\\ \phantom{....................}||\\\ce{H3C - (CH2)2 - CH2 - C - H }\end{array}\] |
Comparing these molecular formulae and assigning the number of carbon atoms as ‘n’, the following general formula is deduced: CnH2nO/CnH2n-1CHO (where n = 1,2,3,...)
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|\phantom{....................}\\
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