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Question
An urn contains twenty white slips of paper numbered from 1 through 20, ten red slips of paper numbered from 1 through 10, forty yellow slips of paper numbered from 1 through 40, and ten blue slips of paper numbered from 1 through 10. If these 80 slips of paper are thoroughly shuffled so that each slip has the same probability of being drawn. Find the probabilities of drawing a slip of paper that is white and numbered higher than 12 or yellow and numbered higher than 26.
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Solution
P(White and numbered higher than 12 or Yellow and numbered higher than 26) = P(White and numbered higher than 12) + P(Yellow and numbered higher than 26)
= `8/80 + 14/80`
= `22/80`
= `11/40`
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\[\frac{1}{14}\]
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