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An urn contains twenty white slips of paper numbered from 1 through 20, ten red slips of paper numbered from 1 through 10, forty yellow slips of paper numbered from 1 through 40, and ten - Mathematics

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प्रश्न

An urn contains twenty white slips of paper numbered from 1 through 20, ten red slips of paper numbered from 1 through 10, forty yellow slips of paper numbered from 1 through 40, and ten blue slips of paper numbered from 1 through 10. If these 80 slips of paper are thoroughly shuffled so that each slip has the same probability of being drawn. Find the probabilities of drawing a slip of paper that is white and numbered higher than 12 or yellow and numbered higher than 26.

बेरीज
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उत्तर

P(White and numbered higher than 12 or Yellow and numbered higher than 26) = P(White and numbered higher than 12) + P(Yellow and numbered higher than 26)

= `8/80 + 14/80`

= `22/80`

= `11/40`

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पाठ 16: Probability - Solved Examples [पृष्ठ २९२]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
पाठ 16 Probability
Solved Examples | Q 8.(e) | पृष्ठ २९२

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