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Question
Fill in the blank in following table:
| P(A) | P(B) | P(A ∩ B) | P(A ∪ B) |
| `1/3` | `1/5` | `1/15` | .... |
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Solution
P(A) = `1/3` P(B) = `1/5`, P(A ∩ B ) = `1/15`, P(A∪ B) = ?
P (A ∪ B) = P(A) + P(B) – P(A ∩ B)
= `1/3 + 1/5 - 1/15`
= `8/15 - 1/15`
= `7/15`
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