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Fill in the blank in following table: P(A) P(B) P(A ∩ B) P(A ∪ B) 0.35 ... 0.25 0.6

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Question

Fill in the blank in following table:

P(A) P(B) P(A ∩ B) P(A ∪ B)
0.35 ... 0.25 0.6
Sum
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Solution

Here, P(A) = 0.35, P(A ∩ B) = 0.25, P(A ∪ B) = 0.6

We know that P(A ∪ B) = P(A) + P(B) – P(A ∩ B)

∴0.6 = 0.35 + P(B) – 0.25

⇒ P(B) = 0.6 – 0.35 + 0.25

⇒ P(B) = 0.5

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Chapter 14: Probability - EXERCISE 14.2 [Page 307]

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NCERT Mathematics [English] Class 11
Chapter 14 Probability
EXERCISE 14.2 | Q 13. (ii) | Page 307

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