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An urn contains twenty white slips of paper numbered from 1 through 20, ten red slips of paper numbered from 1 through 10, forty yellow slips of paper numbered fr

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An urn contains twenty white slips of paper numbered from 1 through 20, ten red slips of paper numbered from 1 through 10, forty yellow slips of paper numbered from 1 through 40, and ten blue slips of paper numbered from 1 through 10. If these 80 slips of paper are thoroughly shuffled so that each slip has the same probability of being drawn. Find the probabilities of drawing a slip of paper that is red or yellow and numbered 1, 2, 3 or 4

Sum
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Solution

P(Red or yellow and numbered 1, 2, 3 or 4)

= P(Red numbered 1, 2, 3 or 4) + P(Yellow numbered 1, 2, 3 or 4)

= `4/80 + 4/80`

= `8/80`

= `1/10`

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Chapter 16: Probability - Solved Examples [Page 292]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 16 Probability
Solved Examples | Q 8.(c) | Page 292

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