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Question
A box contains 100 bulbs, 20 of which are defective. 10 bulbs are selected for inspection. Find the probability thatat least one is defective
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Solution
Out of 100 bulbs, 10 can be chosen in 100C10 ways.
So, total number of elementary events = 100C10
Probability for at least one defective bulb = 1 – Probability (all 10 are non-defective)
= \[1 - \frac{^{80}{}{C}_{10}}{^{100}{}{C}_{10}}\]
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