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Question
In a lottery, a person chooses six different numbers at random from 1 to 20, and if these six numbers match with six number already fixed by the lottery committee, he wins the prize. What is the probability of winning the prize in the game?
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Solution
Total number of ways in which one can choose six different numbers from 1 to 20 = 20C6
∴ Total number of elementary events = 20C6 = 38760
Hence, there are 38760 combinations of 6 numbers.
Out of these combinations, one is already fixed by the lottery committee.
Favourable number of elementary events = 1
∴ Required probability = \[\frac{1}{38760}\]
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| Elementary events: | w1 | w2 | w3 | w4 | w5 | w6 | w7 |
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| (iv) |
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