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Question
4 cards are drawn from a well-shuffled deck of 52 cards. What is the probability of obtaining 3 diamonds and one spade?
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Solution
Number of ways to drawn 4 cards from a deck of 52 cards = 52C4
∴ n(S) = 52C4
Number of ways to obtain 3 diamonds = 13C3
Number of ways to drawn 1 spade = 13C1
Number of ways to drawn 3 diamonds and one spade = 13C3 × 13C1
Total number of favourable outcomes = 13C3 × 13C1
Hence, the probability of obtaining 3 diamonds and 1 spade = `(""^13C_3 xx ""^13C_1)/(""^52C_4)`
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RELATED QUESTIONS
Which of the following can not be valid assignment of probabilities for outcomes of sample space S = {ω1, ω2,ω3,ω4,ω5,ω6,ω7}
| Assignment | ω1 | ω2 | ω3 | ω4 | ω5 | ω6 | ω7 |
| (a) | 0.1 | 0.01 | 0.05 | 0.03 | 0.01 | 0.2 | 0.6 |
| (b) | `1/7` | `1/7` | `1/7` | `1/7` | `1/7` | `1/7` | `1/7` |
| (c) | 0.1 | 0.2 | 0.3 | 0.4 | 0.5 | 0.6 | 0.7 |
| (d) | –0.1 | 0.2 | 0.3 | 0.4 | -0.2 | 0.1 | 0.3 |
| (e) | `1/14` | `2/14` | `3/14` | `4/14` | `5/14` | `6/14` | `15/14` |
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