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Question
A fair coin with 1 marked on one face and 6 on the other and a fair die are both tossed. Find the probability that the sum of numbers that turn up is (i) 3 (ii) 12
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Solution
One die has 1 and 6 marked on it and the other has 1, 2, 3, 4, 5, 6
∴ Sample space = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
(i) The sum of the given numbers is obtained by the event (1, 2).
Number of favourable outcomes = 1
∴ Probability when the sum of the numbers obtained is 3 = `1/12`
(ii) The sum of the given numbers is obtained by the event (6, 6). Here, number of favourable outcomes = 1
∴ Probability when the sum of the numbers obtained is 12 = `1/12`
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| C1 Probability |
C2 Written Description |
| (a) 0.95 | (i) An incorrect assignment |
| (b) 0.02 | (ii) No chance of happening |
| (c) – 0.3 | (iii) As much chance of happening as not |
| (d) 0.5 | (iv) Very likely to happen |
| (e) 0 | (v) Very little chance of happening |
