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Question
Two unbiased dice are thrown. Find the probability that the total of the numbers on the dice is greater than 10.
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Solution
If two dices are thrown simultaneously, then all the possible outcomes = 62 = 36
∴ Total number of possible outcome, n(S) = 36
Let A = event where the the total of the numbers on the dices is greater than 10
Then the favourable outcomes are as follows:
A = {(5, 6), (6, 5), (6, 6)}
Number of favourable outcomes, n(A) = 3
Hence, required probability, P(A) = P (total of the numbers on the dices is greater than 10) = \[\frac{3}{36} = \frac{1}{12}\]
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