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An urn contains twenty white slips of paper numbered from 1 through 20, ten red slips of paper numbered from 1 through 10, forty yellow slips of paper numbered fr - Mathematics

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प्रश्न

An urn contains twenty white slips of paper numbered from 1 through 20, ten red slips of paper numbered from 1 through 10, forty yellow slips of paper numbered from 1 through 40, and ten blue slips of paper numbered from 1 through 10. If these 80 slips of paper are thoroughly shuffled so that each slip has the same probability of being drawn. Find the probabilities of drawing a slip of paper that is red or yellow and numbered 1, 2, 3 or 4

योग
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उत्तर

P(Red or yellow and numbered 1, 2, 3 or 4)

= P(Red numbered 1, 2, 3 or 4) + P(Yellow numbered 1, 2, 3 or 4)

= `4/80 + 4/80`

= `8/80`

= `1/10`

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अध्याय 16: Probability - Solved Examples [पृष्ठ २९२]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 16 Probability
Solved Examples | Q 8.(c) | पृष्ठ २९२

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C1
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Written Description
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(c) – 0.3 (iii) As much chance of happening as not
(d) 0.5 (iv) Very likely to happen
(e) 0 (v) Very little chance of happening

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