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In a non-leap year, the probability of having 53 tuesdays or 53 wednesdays is ______. - Mathematics

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प्रश्न

In a non-leap year, the probability of having 53 tuesdays or 53 wednesdays is ______.

विकल्प

  • `1/7`

  • `2/7`

  • `3/7`

  • None of these

MCQ
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उत्तर

In a non-leap year, the probability of having 53 tuesdays or 53 wednesdays is `bbunderline(2/7)`.

Explanation:

We know that in a non-leap year, there are 365 days and we know that there are 7 days in a week

∴ 365 ÷ 7 = 52 weeks + 1 day

This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday

∴ Total Outcomes = 7

If this day is a Tuesday or Wednesday, then the year will have 53 Tuesday or 53 Wednesday.

∴P (non-leap year has 53 Tuesdays or 53 Wednesdays) = `1/7 + 1/7 = 2/7`

Hence, the correct option is (B).

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अध्याय 16: Probability - Exercise [पृष्ठ २९९]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 16 Probability
Exercise | Q 18 | पृष्ठ २९९

वीडियो ट्यूटोरियलVIEW ALL [1]

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Which of the following can not be valid assignment of probabilities for outcomes of sample space S = {ω1, ω2,ω3,ω4,ω5,ω6,ω7}

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(d) –0.1 0.2 0.3 0.4 -0.2 0.1 0.3
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