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प्रश्न
In a non-leap year, the probability of having 53 tuesdays or 53 wednesdays is ______.
विकल्प
`1/7`
`2/7`
`3/7`
None of these
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उत्तर
In a non-leap year, the probability of having 53 tuesdays or 53 wednesdays is `bbunderline(2/7)`.
Explanation:
We know that in a non-leap year, there are 365 days and we know that there are 7 days in a week
∴ 365 ÷ 7 = 52 weeks + 1 day
This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday
∴ Total Outcomes = 7
If this day is a Tuesday or Wednesday, then the year will have 53 Tuesday or 53 Wednesday.
∴P (non-leap year has 53 Tuesdays or 53 Wednesdays) = `1/7 + 1/7 = 2/7`
Hence, the correct option is (B).
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| Assignment | ω1 | ω2 | ω3 | ω4 | ω5 | ω6 | ω7 |
| (a) | 0.1 | 0.01 | 0.05 | 0.03 | 0.01 | 0.2 | 0.6 |
| (b) | `1/7` | `1/7` | `1/7` | `1/7` | `1/7` | `1/7` | `1/7` |
| (c) | 0.1 | 0.2 | 0.3 | 0.4 | 0.5 | 0.6 | 0.7 |
| (d) | –0.1 | 0.2 | 0.3 | 0.4 | -0.2 | 0.1 | 0.3 |
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\[\frac{1}{7}\]
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\[\frac{1}{7}\]
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