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प्रश्न
If a letter is chosen at random from the English alphabet, find the probability that the letter is a consonant .
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उत्तर
We know that there are 26 letters in the English alphabet.
So, total number of elementary events, n(S) = 26
Out of the 21 consonants of the English alphabet, one consonant can be chosen in 21C1ways.
So, favourable number of events = 21C1 = 21
Hence, required probability =\[\frac{21}{26}\]
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संबंधित प्रश्न
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| Assignment | ω1 | ω2 | ω3 | ω4 | ω5 | ω6 | ω7 |
| (a) | 0.1 | 0.01 | 0.05 | 0.03 | 0.01 | 0.2 | 0.6 |
| (b) | `1/7` | `1/7` | `1/7` | `1/7` | `1/7` | `1/7` | `1/7` |
| (c) | 0.1 | 0.2 | 0.3 | 0.4 | 0.5 | 0.6 | 0.7 |
| (d) | –0.1 | 0.2 | 0.3 | 0.4 | -0.2 | 0.1 | 0.3 |
| (e) | `1/14` | `2/14` | `3/14` | `4/14` | `5/14` | `6/14` | `15/14` |
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| (a) 0.95 | (i) An incorrect assignment |
| (b) 0.02 | (ii) No chance of happening |
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| (d) 0.5 | (iv) Very likely to happen |
| (e) 0 | (v) Very little chance of happening |
