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Fill in the blank in following table: P(A) P(B) P(A ∩ B) P(A ∪ B) 13 15 115 ....

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प्रश्न

Fill in the blank in following table:

P(A) P(B) P(A ∩ B) P(A ∪ B)
`1/3` `1/5` `1/15` ....
योग
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उत्तर

P(A) = `1/3` P(B) = `1/5`, P(A ∩ B ) = `1/15`, P(A∪ B) = ?

P (A ∪ B) = P(A) + P(B) – P(A ∩ B)

= `1/3 + 1/5 - 1/15`

= `8/15 - 1/15`

= `7/15`

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अध्याय 14: Probability - EXERCISE 14.2 [पृष्ठ ३०७]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 14 Probability
EXERCISE 14.2 | Q 13. (i) | पृष्ठ ३०७

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