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प्रश्न
Which of the following compounds would undergo aldol condensation, which the Cannizzaro reaction and which neither? Write the structures of the expected products of aldol condensation and Cannizzaro reaction.
- Methanal
- 2-Methylpentanal
- Benzaldehyde
- Benzophenone
- Cyclohexanone
- 1-Phenylpropanone
- Phenylacetaldehyde
- Butan-1-ol
- 2, 2-Dimethylbutanal
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उत्तर
Aldehydes and ketones having at least one α-hydrogen undergo aldol condensation.
The compounds (ii) 2-Methylpentanal, (v) Cyclohexanone, (vi) 1-phenylpropanone, and (vii) Phenylacetaldehyde contain one or more α-hydrogen atoms. Therefore, these undergo aldol condensation.
Aldehydes having no α-hydrogen atoms undergo Cannizzaro reactions. The compounds (i) Methanal, (iii) Benzaldehyde, and (ix) 2, 2-dimethylbutanal do not have any α-hydrogen. Therefore, these undergo cannizzaro reactions.
Compound (iv) Benzophenone is a ketone having no α-hydrogen atom and compound (viii) Butan-1-ol is an alcohol. Hence, these compounds do not undergo either aldol condensation or cannizzaro reactions.
Aldol condensation:
(ii)
\[\begin{array}{cc}
\phantom{...................................................}\ce{CH3}\\
\phantom{................................................}|\\
\ce{2CH3CH2CH2 - CH - CHO ->[dil NaOH] CH3CH2CH2 - CH - CH - CH - CH2CH2CH3}\\
|\phantom{...................................}|\phantom{......}|\phantom{......}|\phantom{}\\
\phantom{......}\ce{\underset{2-Methylpentanal}{CH3}}\phantom{....................}\ce{\underset{3-Hydroxy-2,4-dimethyl-2-propylheptanal}{\phantom{..}CH3\phantom{...}OH\phantom{...}CHO}}
\end{array}\]
(v)

(vi)

(vii)

Cannizzaro reaction:
(i)
\[\begin{array}{cc}
\ce{H}\phantom{..............................}\ce{H}\phantom{.......}\ce{H}\phantom{......}\\
\backslash\phantom{..............................}|\phantom{.........}\backslash\phantom{....}\\
\ce{2\phantom{...}C = O + conc.KOH -> H - C - OH + C - OK}\\
/\phantom{..............................}|\phantom{.........}/\phantom{....}\\
\ce{\underset{Methanal}{H}}\phantom{..........................}\ce{\underset{Methanol}{H}}\phantom{.}\ce{\underset{methanoate}{\underset{Potassim}{H}}}\phantom{......}
\end{array}\]
(iii)

(ix)
\[\begin{array}{cc}
\phantom{.....}\ce{CH3}\phantom{............................}\ce{CH3}\phantom{........................}\ce{CH3}\phantom{...}\\
\phantom{}|\phantom{...............................}|\phantom{............................}|\phantom{.}\\
\ce{CH3CH2 - C - CHO ->[conc. NaOH] CH3CH2 - C - CH2 - OH + CH3CH2 - C - C - ONa}\\
\phantom{.....}|\phantom{...............................}|\phantom{............................}|\phantom{....}||\phantom{}\\
\phantom{.........}\ce{\underset{2, 2-Dimethylbutanal}{CH3}}\phantom{...............}\ce{\underset{2, 2-Dimethylbutan-1-ol}{CH3}}\phantom{..........}\ce{\underset{Sodium 2, 2-dimethylbutanoate}{CH3\phantom{.}O}}\phantom{.}
\end{array}\]
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संबंधित प्रश्न
A compound 'A' of molecular formula C2H3OCl undergoes a series of reactions as shown below. Write the structures of A, B, C and D in the following reactions :

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(i) \[\ce{CH3 - CHO}\]
(ii) 
(iii) \[\begin{array}{cc}
\phantom{}\ce{O}\\
\phantom{}||\\
\ce{CH3 - C - CH3}
\end{array}\]
(iv) \[\begin{array}{cc}
\phantom{}\ce{CH3}\\
|\phantom{...}\\
\ce{CH3 - C - CHO}\phantom{..}\\
|\phantom{...}\\
\phantom{}\ce{CH3}\\
\end{array}\]
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\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{....................}\\
\phantom{}\ce{2CH3 - C = O ->[Ba(OH)2] A ->[Δ] B + H2O}
\end{array}\]
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